In a photoelectric effect experiment, photons of energy `5 eV` are incident on the photocathode of work function `3eV`. For photon intensity `I_(A)=10^(15)m^(-2)s^(-1)`, saturation current of `4.0 mu A` is obtained. Sketch the variation of photocurrent `i_(p)` against the anode voltage `V_(a)` in the figure below for photon intensity `I_(A)` ( curve `A`) and `I_(B)=2xx10^(15)m^(-2)s^(-1)` (curve `B`) ( in JEE graph was to be drawn in the answer sheet itself.)

Answer

`(##RES_MOD_PHY_XII_C01_E01_006_A01##)`