Calculate the angular frequency of revolution of an electron occupying the second Bohr orbit of `He^(+)` ion.

Answer

`(V_(0))/(r_(0)).(Z^(2))/(n^(3))=(2.19xx10^(6))/(0.529xx10^(-10))xx(Z^(2))/(n^(3))=2.07xx10^(16)s^(-1)`