Figure shows the variation of frequency of a characterstic x-ray and atomic number.

(i) Name the characterstics x-ray
(ii) Find the energy of photon emitted when this x-ray is emitted by a metal having `z=101`

Answer

(i) `K_(alpha)` (ii) `102 KeV`

Explanation

From graph `gammaK(Z-1)^(2)` where `K` is constant
`sqrt(v)=a(z-1) a=sqrt(K)`
So its `K_(alpha)-x-ray`
Energy of photon `=13.6xx(z-b)^(2)((1)/(n_(1)^(2))-(1)/(n_(2)^(2)))`
For `K_(alpha)n_(1)=1`
`n=2`
`E=13.6xx(100^(2))((1)/(n_(1)^(2))-(1)/(n_(2)^(2)))`
`=102 KeV`