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In a discharge tube when 200 volt potent...

In a discharge tube when `200` volt potential difference is applied `6.25xx10^(18)` electrons move from cathode to anode and `3.125xx10^(18)` singly charged positive ions move from anode to cathode in one second. Then the power of tube is:

A

`100 "watt"`

B

`200"watt"`

C

`300 "watt"`

D

`400"watt"`

Text Solution

Verified by Experts

The correct Answer is:
C
`P=P+P`
`=200xx(6.25xx10^(18)+3.125xx10^(18))xx1.6xx10^(-9)W=300W`
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