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A pulse of light of duration 100 ns is a...

A pulse of light of duration `100 ns` is absorbed completely by a small object initially at rest. Power of the pulse is `30 m W` and the speed of light is `3xx10 ms^(-1)`. The final momentum of the object is :

A

`0.3xx10^(17) kg ms^(-1)`

B

`1.0xx10^(17) kg ms^(-1)`

C

`3.0xx10^(-17) kg ms^(-1)`

D

`9.0xx10^(-17)kg ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B

`"Change in momentum"=("power"xx"total time")/("speed of light")=(Pxxt)/(c )`
`1.0xx10^(-17) kgxxm//s`
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