The work function of Silver and sodium are `4.6 and 2.3 eV, ` respectively . The ratio of the slope of the stopping potential versus frequency plot for silver to that of sodium is

Answer

`1`

Explanation

`KE_(max)=hv-phi`
`eV_(st)=hv-phi`
`V_(st)=((h)/(e ))v=(phi)/(e )`
`y=mx+c`
So slpoe will be `((h)/(e ))`, and it will be same for both the metals.
So ratio of the slopes`=1`