The diagram shows the energy levels for an electron in a certain atom. Which transition shown represents the emission of photon with the most enegy ?

Options

A. `III`
B. `IV`
C. `I`
D. `II`

Answer

A

Explanation

`E=Rhc[(1)/(n_(1)^(2))-(1)/(n_(2)^(2))]`
`E_((4rarr3))=Rhc[(1)/(3^(2))-(1)/(4^(2))]`
`=Rhc[(7)/(9xx16)]=0.05 Rhc`
`E_((4rarr2))=[(1)/(2^(2))-(1)/(4^(2))]`
`-Rhc[(3)/(16)]=0.2 Rhc`
`E_((2rarr1))=Rhc[(1)/((1)^(2))-(1)/((2)^(2))]`
`=(8)/(9)Rhc= -0.9 Rhc`
`:.` Thus, III transition gives most energy.