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The graph between the stopping potential...

The graph between the stopping potential `V_(0)` and frequency `v` for two different metal plates `P` and `Q` are shown in the figure. Which of the metals has greater threshold wavelength and work function.

Text Solution

Verified by Experts

`eV_(s)= hv-W`
`W=(hc)/(lambda_(th))`
From graph,
`W_(Q) gt W_(p)` So work function of `Q` is greater than `P`
`lambda_(th p) gt lambda_(th Q)`
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Knowledge Check

  • In the diagram, graph are drawn between stopping potential V_ 0 and frequency v for the elements K and Ca. According this to diagram

    A
    the work functions of K and Ca are equal
    B
    the work function of K is greater than that of Ca
    C
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    D
    no information can be obtained about the work function

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    A
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    B
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    C
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    D
    2.09 ev

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