One end of a long string of linear mass dnesity `8.0xx10^(-3)kgm^(-1)` is connected to an electrically driven tuning fork of frequency 256 Hz. The other end passes over a pulley and is tied to a pan containing a mass of 90 kg. The pulley end absorbs all the incoming energy so that reflected waves at this end have negligible amplitude. At `t=0` the left end (fork end) of the string `x=0` has zero transverse displacement `(y=0)` and is moving along positive y-direction. The amplitude of the wave is 5.0 cm. Write down the transverse displacement y as function of x and t that describest the wave on the string.

Answer

`y = 0.5 sin (1609 t - 4.84x)`

Explanation

`v=sqrt((T)/(mu))=sqrt((90xx9.8)/(8xx10^(-3)))=105sqrt(10)m//s`
`f=256Hz,A=5cm=0.05 m`
Equation of the wave
`:. y=A sin (omegat -kx)`
`=0.05 sin(2 pift - (2pif)/(v)x)`
`=0.05 sin(1609 t - 4.84x)`