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A whistle emitting a sound of frequency `440 H`z is tied to string of `1.5 m` length and rotated with an angular velocity of `20 rad//sec` in the horizontal plane. Then the range of frequencies heard by an observer stationed at a large distance from the whistle will `(v=330 m//s)`

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The correct Answer is:
`403.3 Hz` to 484 Hz
`Deltaf_(1)=f_(0)((v)/(v-v_(S)))=440((330)/(330-20xx1.5))=484Hz`
`f_(2)=f_(0)((v)/(v+v_(S)))=440((330)/(330+20xx15"))=403.3Hz`
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