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Two tuning forks with natural frequencie...

Two tuning forks with natural frequencies of `340 Hz` each move relative to a stationary observer. One fork moves away form the observer, while the other moves towards him at the same speed. The observer hears beats of frequency `3 Hz`. Find the speed of the tuning fork.

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The correct Answer is:
`1.5 m//s`

`Delta f=f_(0)((v)/(v-v_(S)))-f_(0)((v)/(v+v_(S)))=3`
`rArr 3=340[(330)/(330-V_(S))-(330)/(330+V_(S))]rArr V_(S)=1.5m//s`
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Two tuning forks with natural frequencies 340 H_(Z) each move relative to a stationary observer . One forks moves away from the oberver while the other moves towards him at the same speed . The observer hearts beats of frequency 3 H_(Z) . Find the speed the of the tuning fork (velocity of sound in air is 340 m//s) .

Two tuning forks A and B lying on opposite sides of observer 'O' and of natural frequency 80 Hz move with velocity 10 m//s relative to stationary observer O . Fork A moves away from the observer while the fork B moves towards him. A wind with a speed 10 m//s is blowing in the direction of motion of fork A . Find the beat frequency measured by the observer in Hz. [Take speed of sound in air as 340 m//s ].

An observer moves on the same line on which two sources of sound of frequency 660 Hz are present. The observer observes beat frequency of 10Hz . If speed of sound is 300m//s then speed of the observer is:

Two tuning forks A and B having a frequency of 500 Hz each are placed with B to the right of A. An observer in between the forks in moving towards B with a speed of 25 m/s. The speed of sound is 345 m/s and the wind speed is 5 m/s from A to B. Calculate the difference in the two frequencies heard by observer.

A stationary observer receives sound waves from tow tuning forks, one of which approaches and the other recedes with the same velocity. As this takes place, the observer hears beats of frequency upsilon=2Hz . Find the velocity of each tuning fork if their oscillation frequency is upsilon_0=680Hz and the velocity of sound in air is upsilon_s=340(m)/(s) .

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