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A short circuit occurs in a telephone ca...

A short circuit occurs in a telephone cable having a resistance of `0.45 Omega m^(-1)`. The circuit is tested with a Wheatstone bridge network have values of `100 Omega` and `1110 Omega` respectively. A balance condition is found when the variable resistor has a value of `400 Omega`. Calculate the distance down the cable, where the short has occured.

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The correct Answer is:
40 m
`(100)/(0.45l) = (1110)/(400) rArr l = 40 m`
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