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Consider S = X cos (theta) for X = (2.0 ...

Consider `S = X cos (theta)` for `X = (2.0 pm 0.2) cm, theta = 53 pm 2^(@)`. Find S.

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The correct Answer is:
`S = (1.2 pm 0.18) cm`
`S=xcos theta=(2)cos53^(@)=(2)((3)/(5))=1.2`
`(DeltaS)/(S)=(Deltax)/(x)+(Delta(cos theta))/(cos theta)=(Deltax)/(x)+(tan theta)Delta theta rArr Delta S = 1.2`
`[(0.2)/(2)+((4)/(3))(2xx(pi)/(180))]=0.12+0.06=0.18`
`rArr S = (1.2 pm 0.18)cm`
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