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The period of oscillation of a simple pe...

The period of oscillation of a simple pendulum is `T = 2pisqrt(L//g)`. Measured value of L is `20.0 cm` known to `1mm` accuracy and time for 100 oscillations of the pendulum is found to be 90 s using a wrist watch of 1 s resolution. What is the accuracy in the determination of g?

A

0.01

B

0.05

C

0.02

D

0.03

Text Solution

Verified by Experts

The correct Answer is:
D
`d_(1)=0.5+8xx0.01+0.03`
`d_(2)=0.5+4xx0.01+0.03`
`d_(3)=0.5+6xx0.01+0.03`
`d_(n)=(d_(1)+d_(2)+d_(3))/(3)=0.5+0.03+(18xx0.01)/(3)`
`-0.59`
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