`0.89 g` of an `alpha-` amino acid `(A)` gave `0.224` lit. `N_(2)` gas at `NTP` on reaction with `HNO_(2)`. In this process an optically active `(B)` is formed. A as well as `B`, gave cyclic compounds `C` and `D` on intermolecular dehydration Identify `A` to `D`.

Answer

(A) `CH_(3)-underset(underset(NH_(2))(|))(CH)-overset(overset(O)(||))(C)-OH`
(B) `CH_(3)-underset(underset(OH)(|))(CH)-overset(overset(O)(||))(C)-OH`
`(##RES_ORG_CHM_V02_XII_C04_E01_120_A01##)`

Explanation

`n_(N_(2))=(0.224)/(22.4)=10^(-2)`
`because 1` mole of amino = mole of `N_(2)`
`:. 10^(-2)` mole of `N_(2)` is liberated `=10^(-2)` moles of amino acid.
`:. 10^(-2)` mole of amino acid weigh `= 0.89 g`
`:. 1` mole of amino acid weigh `= 89 g`.