Show that the function `f(x)=2x-|x|` is continuous at `x=0` .

Explanation

`lim _{x rightarrow 0_{-}} f(x)=lim _{x rightarrow--} 3 x=0 .`


`
lim _{x rightarrow 0^{+}} f(x)=lim _{x rightarrow 0^{+}} x=0 .
`


We have,
`
lim _{x rightarrow 0_{-}} f(x)=lim _{x rightarrow 0^{-}} f(x)=f(0)
`


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