Determine the value of `k` for which the following function is continuous at `x=3.` `f(x)={(x^2-9)/(x-3),\ \ \ x!=3k ,\ \ \ x=3`

Explanation

Here ,`f(x) ` is continuous at `x=3.`

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therefore

lim _{x rightarrow 3} f(x)=f(3) `

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lim _{x rightarrow 3} f(x)=k`

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