Find the value of the constant `lambda` so that the function given below is continuous at `x=-1` `f(x)={(x^2-2x-3)/(x+1),\ \ \ x!=-1\ \ \ \ \ \ \ \ \ \ lambda,\ \ \ \ \ \ \ \ \ \ \ \ \ x=-1`

Explanation

Here ,`f(x)` is continuous at `x=-1`


So ,
`
lambda=lim _{x rightarrow-1} frac{x^{2}-2 x-3}{x+1}`

`=lim _{x rightarrow-1} frac{(x-3)(x+1)}{x+1}`

`=lim _{x rightarrow-1}(x-3)=-4`