Find the values of `' a '` so that the function `f(x)` defined by `f(x)={(sin^2a x)/(x^2),\ \ \ x!=0\ \ \ 1,\ \ \ \ \ \ \ \ \ x=0` may be continuous at `x=0` .

Explanation

To find the values of \( a \) such that the function

\[
f(x) =
\begin{cases}
\frac{\sin^2(ax)}{x^2} & \text{if } x \neq 0 \\
1 & \text{if } x = 0
\end{cases}
...