`f(x)={(1-x^n)/(1-x),\ \ \ x!=1 ` `,\ \ \ n-1,\ \ \ x=1\ \ \ \ n in N` at `x=1`

Explanation

To determine the continuity of the function \( f(x) \) at \( x = 1 \), we need to analyze the function defined as:

\[
f(x) =
\begin{cases}
\frac{1 - x^n}{1 - x}, & x \neq 1 \\
n - 1, & x = 1
\end{cases}
...