Find the value of the constant `k` so that the given function is continuous at the indicated point: `f(x)={(x^3+x^2-16 x+20)/((x-2)^2),\ \ \ x!=2k ,\ \ \ x=2` at `x=0` .

Explanation

To find the value of the constant \( k \) so that the function

\[ f(x) = \begin{cases} \frac{x^3 + x^2 - 16x + 20}{(x-2)^2} & \text{if } x \neq 2 \\ k & \text{if } x = 2 \end{cases} \]
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