Prove that the function `f(x)={(sinx)/x\ \ \ ,\ \ \ x<0x+1\ \ \ ,\ \ \ xgeq0` is everywhere continuous.

Explanation

When `x<0`, we have



`f(x)=frac{sin x}{x}`



We know that `sin x` as well as the identity function `x` are everywhere continuous. So, the quotient function `frac{sin x}{x}`


When `x>0`, we have



`f(x)=x+1`


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