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The value of f(0), so that the function...

The value of `f(0),` so that the function `f(x)=((27-2x)^(1/3)-3)/(9-3(243+5x)^(1//5))(x!=0)` is continuous, is given by (a)`2/3` (b) 6 (c) 2 (d) 4

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Given,
`f(x)=((27-2x)^(1/3)-3)/(9-3(243+5x)^(1//5))`
`=>lim_(x->0)`f(x)=`((27-2x)^(1/3)-3)/(9-3(243+5x)^(1//5))`
`=>lim_(x->0)((1/3)(27−2x)−2/3(−2))/((−3/5)(243+5x)−4/5(5)) `
`=>2​`
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