The sides of an equilateral triangle are increasing at the rate of `2` `cm`/`sec`. How far is the area increasing when the side is `10` `cm`?

Explanation

Let,

`x=` side and `A=` Area

We know that,

`A=(sqrt(3)x^2)/(4)`

Differentiating both sides w.r.t. `t`

`(dA)/(dt)=(sqrt(3))/(4)*2x*(dx)/(dt)`

Given that, `x=10cm`

`(dx)/(dt)=2cm/s`

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