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The side of a square is increasing at th...

The side of a square is increasing at the rate of `0.1cm`/`sec`. Find the rate of increase of its perimeter.

Text Solution

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Given that,
`(da)/(dt)=0.1 cm`/`sec`
We know that, `P=4a`
where `a=` side
Differentiating w.r.t. `t`
`(dP)/(dt)=4(da)/(dt)`
`(dP)/(dt)=4*(0.1)=0.4 \ cm`/`sec`

Answer is:
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