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The radius of a sphere is changing at th...

The radius of a sphere is changing at the rate of `0.1 cm`/`sec`. The rate of change of its surface area when the radius is `200 cm` is

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Verified by Experts

We know that,
`S=4pir^2`
Given that, `r=200cm, (dr)/(dt)=0.1 cm`/`sec`
`(dS)/(dt)=8pir(dr)/(dt)`
`(dS)/(dt)=8pi*200*0.1`
`(dS)/(dt)=160pi`
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