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A cylindrical vessel of radius 0.5 m is ...

A cylindrical vessel of radius `0.5 m` is filled with oil at the rate of `0.25 pi  m^3`/`min`. The rate at which the surface of the oil is rising, is

A

(a) `1 m`/`min`.

B

(b) `2 m`/`min`.

C

(c) `5 m`/`min`.

D

(d) `1.25 m`/`min`.

Text Solution

Verified by Experts

The correct Answer is:
(a) `1 m`/`min`.

Given,
`r=0.5m` and `(dV)/(dt)=0.25 m^3`/`min`

We know that,
`V=pir^2h`
`(dV)/(dt)=pir^2(dh)/(dt)`
`0.25pi=pi(0.25)(dh)/(dt)`
`(dh)/(dt)=1`

Hence, correct option is a)
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