The rate of change of volume of a sphere is equal to the rate of change of its radius, then its radius is equal to

Explanation

Given that,

`(dV)/(dt)=(dr)/(dt)`

We know that,

`V=frac{4}{3} pir^3`

`(dV)/(dt)=4pir^2(dr)/(dt)`

`(dr)/(dt)=4pir^2(dr)/(dt)`

`(1-4pir^2)(dr)/(dt)=0`

`r^2=frac{1}{4pi}`

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