Find the percentage error in calculating the volume of a cubical box if an error of 1% is made in measuring the length of edges of the cube.

Explanation

let the edge of cube be`x`

volume = `x^3`

`(dv)/(dx) = 3x^2 `

`dx/x xx 100 = 1`

`dx = x/100`

`dv = d v = (dv)/(dx) xx dx = 3x^2 xx x/100`

`= (3x^3)/100`

`(dv)/v xx 100 = (3x^3)/(100 xx v) xx 100`

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