Find the approximate value of `f(3. 02)` , where `f(x)=3x^2+5x+3` .

Explanation

Here, we will use the definition of derivatives:

`f'(x) = (f(x+Deltax)-f(x))/((x+Deltax)-x)`

`f'(x) = (f(x+Deltax)-f(x))/(Deltax)`

Here, `x = 3 and Deltax = 0.02`

`:. f'(3) = (f(3+0.02) - f(3))/0.02->(1)`

Here, `f'(x) = 6x+5`

`:. f'(3) = 6(3)+5 = 23`

`f(3) = 3(9)+5(3)+3 = 45 `

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