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The radius of a sphere shrinks from 1...

The radius of a sphere shrinks from 10 to 9.8 cm. Find approximately the decrease in its volume.

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Volume of a sphere,
`V=4/3πr3`
`∴(dV)/(dr)=4/3π(3r^2)`
`⇒(dV)/(dr)=4πr^2`
Here,
`r=10cm`,`dr=9.8−10=−0.2cm`
`∴(dV)/(−0.2)=4π(10)^2`
`⇒dV=400πxx(−0.2)`
`=−80π`
So, decrease in volume of the sphere is `80πcm^3.`
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