The pressure `p` and the volume `v` of a gas are connected by the relation `p v^(1. 4)=con s tdot` Find the percentage error in `p` corresponding to a decrease of 1/2% in `vdot`

Explanation

`pv^(1/4) = c`
`p= cv^(-1/4)`
`ln p = ln(cv^(-1/4))`
`ln p = ln c + (-1/4)ln v`
now, `(dp)/p = 0- 1/4(dv)/v`
`(dp)/p = -1/4 (dv)/v`
`(dp)/p = -1/4(-1/2%)`
`= 1/8%`