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Find approximate value of 1/(sqrt(25....

Find approximate value of `1/(sqrt(25. 1))` using differentials.

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Let `y=1/sqrtx`
and `x=25`
`x+trianglex=25.1`
`impliestrianglex=0.1`
For `x=25,`
`y=1/sqrt{25}=0.2`
Let `dx=trianglex=0.1`
As`y=1/sqrtx`,
...
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