Use differentials to find the approximate value of `(17)^(1/4)`

Explanation

Let `y=x^{1/4}`

and `x=16`

`x+trianglex=17`

`impliestrianglex=1`

For `x=16,`

`y=(16)^{1/4}=2`

Let `dx=trianglex=1`

As`y=x^{1/4}`,

...