A sphere of radius 100 mm shrinks to radius 98 mm, then the approximate decrease in its volume is `12000\ pi\ m m^3` (b) `800\ pi\ m m^3` (c) `80000\ pi\ m m^3` (d) `120\ pi\ m m^3`

Explanation

Given, `r=100 {~mm}`


`{r}+\Delta {r}=98 {~mm}`



`\Rightarrow \Delta {r}=-2 {~mm}`


Volume of sphere `{V}=\frac{4}{3} \pi {r}^{3}`
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