If the ratio of base radius and height of a cone is 1:2 and percentage error in radius is `lambda%` , then the error in its volume is `lambda%` (b) `2lambda%` (c) `3lambda%` (d) none of these

Explanation

Volume of cone` {V}=\frac{1}{3} \pi {r}^{2} {~h}`


Given, `\frac{r}{h}=\frac{1}{2}`



`\Rightarrow {V}=\frac{2}{3} \pi {r}^{3} `


`\frac{{dV}}{{dr}}=2 \pi {r}^{2}`
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