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Find the slope of the normal to the c...

Find the slope of the normal to the curve `x=1-asintheta` , `y=b\ cos^2theta` at `theta=pi/2` .

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Given, `x=1-asintheta` , `y=b\ cos^2theta`

`(dx)/(d theta)=-acos theta`

`(dy)/(d theta)=-2bcos theta sin theta`

Let `m` be the slope of tangent and `n` be the slope of normal

`mn=-1`

`n=-1/m`

...
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