Find the points on the curve `y^2=2x^3` at which the slope of the tangent is 3.

Answer

Our point is `(2,4)`

Explanation

Let us consider `(x_{1}, y_{1})` be the required point.

So ATQ,
$$ y^{2}=2 x^{3} $$
Since `(x_{1} y_{1})` lies on a curve , `y_{1}^{2}=2 x_{1}^{3} \ldots` (1)
$$
\begin{aligned}
...