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At what point of the curve y=x^2 does...

At what point of the curve `y=x^2` does the tangent make an angle of `45o` with the x-axis?

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Verified by Experts

The correct Answer is:
Point is `(1 / 4,1 / 2)`

Given, Slope of the tangent `=m=\tan 45^{\circ}=1`

`y^{2}=x`

`2 y( dy / dx)=1`

`dy / dx=1 / (2y)`

slope of the tangent `= dy / dx`

`1 = 1/(2y)`

`y=1 / 2`

`y^{2}=x`

...
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