Find the equation of the tangent to the curve `y=-5x^2+6x+7` at the point `(1//2,\ 35//4)` .

Answer

`y=x+frac{33}{4}`

Explanation

Given :
$$ y=-5 x^{2}+6 x+10 $$
For slope at `x=\frac{1}{2}` :
$$ y^{\prime}\left(\frac{1}{2}\right)=m=-10 x+6=1 $$
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