Find the equation of the tangent to the curve `y=(x-7)/((x-2(x-3)` at the point where it cuts the x-axis.

Answer

`20x + y -140 = 0`

Explanation

Given, equation of curve is
$$ y=\frac{(x-7)}{(x-2)(x-3)} $$
To find the intersection of given curve with `X`-axis, putting `y=0` in equation 1, we get,
$$ 0=\frac{x-7}{(x-2)(x-3)} $$
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