Find the equation of tangent line to `y=2x^2+7` which is parallel to the line `4x-y+3=0` .

Answer

`4 x-y+5=0
`

Explanation

Given,

`y=2 x^{2}+7 `


`m_{1}=\frac{d y}{d x}=4 x`


The slope of `4 x-y+3=0`
$$
\begin{aligned}
&m_{2}=\frac{4}{1}=4 \\
&m_{1}=m_{2} \Rightarrow \text { Lines are parallel } \\
...