Find the equations of the tangent and the normal to the curve `y=x^4-6x^3+13 x^2-10 x+5` at `x=1` at the indicated points

Answer

`x+2 y-7=0`

Explanation

Given,
$$ \begin{aligned} &y=x^{4}-6 x^{3}+13 x^{2}-10 x+5 \\ &\Rightarrow \frac{d y}{d x}=4 x^{3}-18 x^{2}+26 x-10 \end{aligned} $$
$$
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