Find the equations of the tangent and the normal to the curve `y^2=4x` at `(1,\ 2)` at indicated points.

Explanation

Given, `y^2=4x`
at `P(1,\ 2)`


Slope of tangent `y=sqrt(4x)`


`(dy)/(dx)=(2)/(2sqrt(x))`


`((dy)/(dx))_(P(1,2))=(2)/(2sqrt(1))=2/2=1`



Equation of tangent at `P(1,2)`


`y-2=m(x-1)`


`y-2=1(x-1)`


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