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Find the equation of the tangent line to the curve `y=x^2-2x+7` which is parallel to the line `2x-y+9=0`

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The equation of given curve is `y=x^{2}-2 x+7`
On differentiating with respect to `x`, we get:
`frac{d y}{d x}=2 x-2`
The equation of the line is `2 x-y+9=0`
`Rightarrow y=2 x+9`
This is of the form `y=m x+c`
`therefore` slope of the line `=2`
If a tangent is parallel to the line `2 x-y+9=0`, then the slope of the tangent is equal to the slope of the line.
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