Find the equation of the tangent line to the curve `y=x^2-2x+7` which is perpendicular to the line `5y-15 x=13` .

Explanation

The equation of the given curve is `y=x^{2}-2 x+7`

On differentiating with respect `x`, we get:

`frac{d y}{d x}=2 x-2`

The equation of the line is `5 y-15 x=13`

`5 y-15 x=13` `Rightarrow 5 y=15 x+13`

`Rightarrow frac{5 y}{5}=frac{15 x}{5}+frac{13}{5} ldots ldots ldots ldots ldots ldots .`[ dividing both the sides by 5]

`Rightarrow y=3 x+frac{13}{5}`

This is of the form `y=m x+c`

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