Find the equation of the tangent to the curve `x=sin3t` , `y=cos2t` at `t=pi/4` .

Explanation

To find the equation of the tangent to the curve defined by the parametric equations \( x = \sin(3t) \) and \( y = \cos(2t) \) at \( t = \frac{\pi}{4} \), we will follow these steps:

### Step 1: Differentiate the parametric equations
We need to find the derivatives \( \frac{dx}{dt} \) and \( \frac{dy}{dt} \).

1. Differentiate \( x = \sin(3t) \):
\[
\frac{dx}{dt} = 3\cos(3t)
...