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Find the equation of the tangents to the...

Find the equation of the tangents to the curve `3x^2-y^2=8`, which passes through the point `(4/3,0)`.

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We have,
`3 x^{2}-y^{2}=8 ldots(i)`

Differentiating both sides w.r.t x, we get
`6 x-2 y frac{d y}{d x}=0 `
...
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