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Find the slope of the normal at the p...

Find the slope of the normal at the point `' t '` on the curve `x=1/t ,\ \ y=t` .

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Given,`x=1/t ,\ \ y=t`
`(dx)/(dt)​=−1/t^2,(dy)/(dt)​=1`
Now slope of tangent
`(dy)/(dx)​=((dy)/(dt))​/((dx)/(dt))=-t^2`
Let slope of normal is `m_2`​ and slope of tangent is `m_1`​ and they are perpendicular to each other.
`m_1​×m_2​=−1`
...
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