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Find the coordinates of the point on the curve `y^2=3-4x` where tangent is parallel to the line `2x+y-2=0` .

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Given,`y=2-2x`
Slope `=-2`
as,`y^2=3-4x`
`2y.(dy/dx)​=-4`
`2y×(-2)=(-4)`
`y=1`
...
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